x-y-1分之x²-2xy+y²-1 化简
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x-y-1分之x²-2xy+y²-1 化简
=[(x-y)²-1]/(x-y-1)
=(x-y+1)(x-y-1)/(x-y-1)
=x-y+1
（x²-2xy+y²-1)/(x-y-1)
=[(x-y)²-1]/(x-y-1)
=(x-y+1)(x-y-1)/(x-y-1)
=x-y+1
x-y-1分之x²-2xy+y²-1 化简
=[(x-y)²-1]/(x-y-1)
=(x-y+1)(x-y-1)/(x-y-1)
=x-y+1
（x²-2xy+y²-1)/(x-y-1)
=[(x-y)²-1]/(x-y-1)
=(x-y+1)(x-y-1)/(x-y-1)
=x-y+1