已知｜x-2｜+(3x+y+m）²=0,当m为何值时,y≥0?

已知｜x-2｜+(3x+y+m）²=0,当m为何值时,y≥0?

｜x-2｜+(3x+y+m）²=0
x-2=0,3x+y+m=0
x=2
y+m=-6
y=-6-m
∵y≥0
∴-6-m≥0
m≤-6

｜x-2｜+(3x+y+m）²=0
x-2=0
3x+y+m=0
x=2
6+y+m=0
y=-6-m
y≥0
-6-m≥0
m≤-6

｜x-2｜+(3x+y+m）²=0
则必有：
x-2=0
3x+y+m=0
解得：
x=2
y=-3x-m=-6-m≥0
m≤-6