已知tana=3,求tan(a+π/4)的值
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已知tana=3,求tan(a+π/4)的值
tan(a+π/4)
=(tana+tan(π/4))/[1-tana *tan(π/4)]
=(3+1)/(1-3*1)
=-2
tan(a+π/4)=(tana+tanπ/4)/(1+tana*tanπ/4)=(3+1)/(1+3*1)=1
已知tana=3,求tan(a+π/4)的值
tan(a+π/4)
=(tana+tan(π/4))/[1-tana *tan(π/4)]
=(3+1)/(1-3*1)
=-2
tan(a+π/4)=(tana+tanπ/4)/(1+tana*tanπ/4)=(3+1)/(1+3*1)=1