说明代数式[(x-y)^2-(x+y)(x-y)] ÷(-2y)+y的值,与y的值无关

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说明代数式[(x-y)^2-(x+y)(x-y)] ÷(-2y)+y的值,与y的值无关

[(x-y)^2-(x+y)(x-y)] ÷(-2y)+y
=-(x^2+y^2-2xy-x^2+y^2)/(2y)+y
=2x

[(x-y)^2-(x+y)(x-y)] ÷(-2y)+y
=[x^2+y^2-2xy-x^2+y^2] ÷(-2y)+y
=x
不含y,所以与y无关。