求值域y=4x-1\3x+1
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求值域y=4x-1\3x+1
分离常数法:y=[4(x+1/3)-7/3]/3(x+1/3)=4/3-7/9(x+1/3),
所以值域为y不等于4/3
题目是y=4x-(1/3x)+1还是y=4x-1/(3x+1)?
求值域y=4x-1\3x+1
分离常数法:y=[4(x+1/3)-7/3]/3(x+1/3)=4/3-7/9(x+1/3),
所以值域为y不等于4/3
题目是y=4x-(1/3x)+1还是y=4x-1/(3x+1)?