(2y+1)²+3(2y+1)+2=0 用因式分解法解方程
来源:学生学帮网 编辑:学帮网 时间:2024/07/03 01:09:18
(2y+1)²+3(2y+1)+2=0 用因式分解法解方程
(2y+1)²+3(2y+1)+2=0
((2y+1)+1)((2y+1)+2)=0
(2y+2)(2y+3)=0
2y+2=0或2y+3=0
y=-1或y=-3/2
(2y+1)²+3(2y+1)+2=0 用因式分解法解方程
(2y+1)²+3(2y+1)+2=0
((2y+1)+1)((2y+1)+2)=0
(2y+2)(2y+3)=0
2y+2=0或2y+3=0
y=-1或y=-3/2