具体过程
来源:学生学帮网 编辑:学帮网 时间:2024/06/29 21:50:11
√(x-1)=t x=1+t^2 dx=2tdt
积分=∫(0,1)2t^2dt/(1+t^2)
=∫(0,1)(2-2/(1+t^2))dt
=2-2arctant|(0,1)
=2-π/2
√(x-1)=t x=1+t^2 dx=2tdt
积分=∫(0,1)2t^2dt/(1+t^2)
=∫(0,1)(2-2/(1+t^2))dt
=2-2arctant|(0,1)
=2-π/2