（2x+1）²－（x+3）²-（x-1）²+1要有非常详细的解答过程,

（2x+1）²－（x+3）²-（x-1）²+1要有非常详细的解答过程,

=(2x+1)^2-(x+3)^2-[(x-1)^2-1]
=(2x+1+x+3)*(2x+1-x-3)-(x-1+1)*(x-1-1)
=(x-2)*(3x+4-1)
=2*(x+2)*(x-2)
=2x^2-8