∫π/2到-π/2√cosx-cosx^3dx=
来源:学生作业学帮网 编辑:学帮网 时间:2024/07/06 18:37:04
∫π/2到-π/2√cosx-cosx^3dx=
∫π/2到-π/2√cosx-cosx^3dx
=-2∫(0,π/2)√cosx(1-cos²x)dx
=-2∫(0,π/2)sinx√cosxdx
=2∫(0,π/2)√cosxdcosx
=2*(2/3)(cosx)^(3/2)|(0,π/2)
=-4/3
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来源:学生作业学帮网 编辑:学帮网 时间:2024/07/06 18:37:04
∫π/2到-π/2√cosx-cosx^3dx=
∫π/2到-π/2√cosx-cosx^3dx
=-2∫(0,π/2)√cosx(1-cos²x)dx
=-2∫(0,π/2)sinx√cosxdx
=2∫(0,π/2)√cosxdcosx
=2*(2/3)(cosx)^(3/2)|(0,π/2)
=-4/3