学帮网解算式：2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)加急
来源：学生作业学帮网 编辑：学帮网 时间：2024/07/07 02:11:52
解算式：2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)
加急
2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)
=[1/(x+1) -1/(x+3)]+[1/(x+3) -1/(x+5)]+.+[1/(x+2001) -1/(x+2003)]
= 1/(x+1) - 1/(x+2003)
= [(x+2003)-(x+1)]/[(x+1)(x+2003)]
= 2002/[(x+1)(x+2003)]