a>b>c,证明b(c^2)+c(a^2)+a(b^2)

a>b>c,证明b(c^2)+c(a^2)+a(b^2)

a^2b+b^2c+c^2a-ab^2-bc^2-ca^2=ab(a-b)+bc(b-c)-ac(a-b+b-c)=(ab-ac)*(a-b)+(bc-ac)*(b-c)=(a-b)*(a-c)*(b-c)＞0