(1/x-y-1/x+y)*x²-2xy+y²/(y+1)²-(y-1)²
来源:学生作业学帮网 编辑:学帮网 时间:2024/07/04 10:26:05
(1/x-y-1/x+y)*x²-2xy+y²/(y+1)²-(y-1)²
原式=(x+y+x-y)/(x+y)(x-y)*(x-y)²/(y+1+y-1)(y+1-y+1)
=2x/(x+y)(x-y)*(x-y)²/4y
=(x²-xy)/(2xy+2y²)
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来源:学生作业学帮网 编辑:学帮网 时间:2024/07/04 10:26:05
(1/x-y-1/x+y)*x²-2xy+y²/(y+1)²-(y-1)²
原式=(x+y+x-y)/(x+y)(x-y)*(x-y)²/(y+1+y-1)(y+1-y+1)
=2x/(x+y)(x-y)*(x-y)²/4y
=(x²-xy)/(2xy+2y²)