The period of the earth around the sun is 地球围绕太阳旋转的1 year and its distance is 150 million km from 周期为1年,设地球距the sun.An asteroid in a circular orbit around 离太阳1.5亿千米.the sun is at a distance 581 million km
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The period of the earth around the sun is 地球围绕太阳旋转的
1 year and its distance is 150 million km from 周期为1年,设地球距
the sun.An asteroid in a circular orbit around 离太阳1.5亿千米.
the sun is at a distance 581 million km from 已知另一围绕太阳旋
the sun.转的行星距离太阳5.81
What is the orbital velocity of the asteroid?亿千米.
Assume there are 365 days in one year.求:行星的轨道速度.
Answer in units of m/s (设一年有365天)
(单位:m/s)
设太阳、地球、行星的质量分别为M、m1、m2,地球和行星的轨道半径分别为R1、R2,周期分为T1、T2
太阳对地球和行星的万有引力充当向心力,根据牛顿第二定律可知
地球围绕太阳旋转时有
利用开普勒第三定律先求出行星运动的周期,再根据圆周运动的知识求出轨道速度。
或者直接利用那个万有引力定律和圆周运动知识求解。
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