two person are running towards each other.they are 37m apart.if one is accelerating from rest at 0.5m/s^2 and the other was a;ready moving at 3.1m/s and maintains herspeed.a)how long before they crunch togetherb) how fast was the accelerating player
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two person are running towards each other.they are 37m apart.if one is accelerating from rest at 0.5m/s^2 and the other was a;ready moving at 3.1m/s and maintains herspeed.
a)how long before they crunch together
b) how fast was the accelerating player going
c)how far has each person run
咱不需要翻译只要解题~
如有不明或需要翻译这题可以跟我说
两个人都奔向对方。他们的距离是37米。如果一个人从静止加速在0.5米/秒^ 另一个是,一直移动3.1米/秒,并保持他的速度。
a)他们是什么时候碰在一起
b)加速的人的速度是什么
c)两个人分别跑了多少
a) 1/2 *0.5*t^2 + 3.1*t = 37
t = 7.4543 s
b) v = 0.5* 7.4543 = 3.72715 m/s
c) 1/2 *0.5*t^2 = 1/2 *0.5*7.4543 ^2 = 13.8916 m
3.1*t = 3.1* 7.4543 = 23.1083 m
也许我能答这题,可你要先翻译好,哈哈。
解
A 假设他们是在t秒后碰在一起则t秒后2人运动的路程加起来是37米即
(1/2)at²+Ut=37=1/2 *0.5*t^2 + 3.1*t 解得 t = 7.4543 s
B加速人的速度。 加速度是a 时间是t 有公式U=at得U=0.5* 7.4543 =3.72715 m/s
C就是A中的2个位移 1个是X=(1/2)at&s...
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解
A 假设他们是在t秒后碰在一起则t秒后2人运动的路程加起来是37米即
(1/2)at²+Ut=37=1/2 *0.5*t^2 + 3.1*t 解得 t = 7.4543 s
B加速人的速度。 加速度是a 时间是t 有公式U=at得U=0.5* 7.4543 =3.72715 m/s
C就是A中的2个位移 1个是X=(1/2)at²= 1/2 *0.5*7.4543 ^2 = 13.8916 m
1个是X=Ut=3.1* 7.4543 = 23.1083 m
他们两个加起来是37m
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