真么写已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac 求角am=an已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac求角am=an
来源:学生作业学帮网 编辑:学帮网 时间:2024/06/30 09:05:32
真么写已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac 求角am=an已知如图ab=ac ad=ae ab dc相交于点m ac be相交于点n,角bab=角eac
求角am=an
证明:∵AB=AC,AD=AE,∠DAB=∠EAC,
∴∠DAC=∠AEB,
∴△ACD≌△ABE,
∴∠D=∠E,
又AD=AE,∠DAB=∠EAC,
∴△ADM≌△AEN.
am=an
30度
角bab=角eac这个是什么条件呀
◆题目表达不太清楚,在此设AB交CE于M,AC交BD于N.
证明:∵AB=AC;AD=AE;∠DAB=∠EAC.
∴⊿DAB≌⊿EAC(SAS),∠D=∠E.
∵∠DAB=∠EAC.
∴∠DAB-∠BAC=∠EAC-∠BAC,即∠DAN=∠EAM.
∵∠D=∠E(已证);AD=AE(已知);∠DAN=∠EAM(已证).
∴⊿DAN≌⊿EAM(AAS),AM=AN.
证明:∵AB=AC,AD=AE,∠DAB=∠EAC,
∴∠DAC=∠AEB,
∴△ACD≌△ABE,
∴∠D=∠E,
又AD=AE,∠DAB=∠EAC,
∴△ADM≌△AEN.
AM=AN
如图,已知AD/DB=AE/EC,求证 :AD/AB=AE/AC.
已知:如图,AC/AD=AB/DE=BC/AE.求证AB=AE
已知,如图,AD/AC=DE/AB=AE/BC,求证AB=AE
已知,如图,AD:AC=DE:AB=AE:BC 求证:AB=AE
如图,已知:AB=AE,AC=AD,AC⊥AD,AB⊥AE.求证:ED⊥BC.
已知:如图,AD/AB=AE/BC求证:AD/AE=DB/EC和AB/DB=AC/EC
已知:如图,AD/AB=AE/BC求证:AD/AE=DB/EC和AB/DB=AC/EC
如图,DE//BC,请问AD:AC=AE:AB?AD:AE=AB:AC?
已知如图AB=AC,求证AB²=AD×AE
初三放缩与相似性已知:如图,线段BD与CE相交于点A,AD:BD=AE:CE求证:AB:AC=AD:AE
如图,已知AD//BC,AD=BC,AE⊥AD,AF⊥AB,AE=AD,AB=AF.求证:AC=EF.
已知:如图,线段BD与CE相交与点A,BD分之AD=CE分之AE 求证:(1)AB分之AD=AC分之AE (2) AC AB=AE AD2(1)的课后练习~
已知,如图AB=AC,AD=AE,LBAC=LDAE,求证:LB=LC
已知;如图,ab=ac,bd=ce,ad=ae.求证be=cd.
全等三角形如图,已知AB=AC,AD=AE,求证BD=CE.
如图,已知AB=AC,AD=AE.求证BD=CE
如图13,已知AB=AC,AD=AE,求证BD=CE
如图,已知,AB=AC,AD=AE,求证:BD=CE