一元二次方程化为顶点式y=5750-(x-10)[1000-30(x-10)]

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一元二次方程化为顶点式
y=5750-(x-10)[1000-30(x-10)]

y=30(x-80/3)^2-7750/3

你好,
y=5750-(x-10)[1000-30(x-10)]
=5750-(x-10)1000+30(x-10)^2
=18750-7000x+30x^2
=30(x-350/3)^2-1225000/3+18750
=30(x-350/3)^2-1225000/3+56250/3
=30(x-350/3)^2-1168750/3
谢谢