1-2+3-4+5.+2011 1-2+3-4+6.-2010
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1-2+3-4+5.+2011 1-2+3-4+6.-2010
1-2+3-4+5.+2011
=(1-2)+(3-4)+(5-6).(2009-2010)+2011
=-1-1-1...-1+2011
=-1005+2011
=1006
1-2+3-4+5-6.-2010
=(1-2)+(3-4)+(5-6).(2009-2010)
=-1-1-1...-1
=-1005
-1005
1-2+3-4+5..........+2011
=(1-2)+(3-4)+...(1999-2000)+2011
=-1-1-...-1+2011
=-1*2000/2+2011
=-1000+2011
=1011
1-2+3-4+5..............-2010
==-1-1-...-1
=-1*2000/2
=-1000
先加后减 即 先求1+3+5...... + 2011 = ((1+2011)*((2011-1)/2+1))/2=
再求减法的 -(2+4+6+....+2010) 一样算 就是等差数列求和啊。。。
1-2+3-4+5..........+2011
=(1-2)+(3-4)+...(1999-2000)+2011
=-1-1-...-1+2011
=-1*2000/2+2011
=-1000+2011
=1011
1-2+3-4+5..............-2010
==-1-1-...-1
=-1*2000/2
=-1000 我觉得应该是这样!
1+2+3+4+5.加到2011等于多少?
1-2+3-4+5.+2011 1-2+3-4+6.-2010
1,2,3,4,5.
1,2,3,4,5.
1,2,3,4,5.
(1+3+5...+2009+2011)-(2+4+6+...+2010+2012)的值
(1+3+5.+2009+2011)-(2+4+6...2010+2012=
1/2+1/3+1/4+1/5.+1/100,
1=1² 1+3=2².1+3+5.+2011=?
(1-1/2*2)(1-1/3*3)(1-1/4*4).(1-1/2010*2010)(1-1/2011*2011)
2011-1/2×2011-1/3×(2011-1/2×2011)-...-1/2011×(2011-1/2×2011-...-1/2010×2011)
7,1,2,3,4,5.
1+2+3+4+5.+100=
1+2+3+4+5.+9999999=?
1-2+3-4+5.+99-100
1+2+3+4+5.+1000=?
1+2+3+4+5.+50=?
1+2+3+4+5.+10=