化简y的平方-2y+1分之xy-x-y+1

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化简y的平方-2y+1分之xy-x-y+1

(xy-x-y+1)/(y²-2y+1)
=(x-1)(y-1)/(y-1)²
=(x-1)/(y-1)

原式=[x(y-1)-(y-1)]/(y-1)²
=(y-1)(x-1)/(y-1)²
=(x-1)/(y-1)