已知sin(兀/4+x)=-3/5,则sin2x的值为?
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已知sin(兀/4+x)=-3/5,则sin2x的值为?
sin(π/4+x)=-3/5
sinxcosπ/4+cosxsinπ/4=-3/5
√2/2(sinx+cosx)=-3/5
sinx+cosx = -3√2/5
(sinx+cosx)^2 = (-3√2/5)^2
sin^2x+cos^2x+2sinxcosx=18/25
1+sin2x=18/25
sin2x = -7/25
sin(π/4+x)=-3/5 sinxcosπ/4+cosxsinπ/4=-3/5 √2/2(sinx+cosx)=-3/5 sinx+cosx = -3√2/5 (sinx+cosx)^2 = (-3√2/5)^2 sin^2x+cos^2x+2sinxcosx=18/25 1+sin2x=18/25 sin2x = -7/25
s = 2*sin(x)-sin(2*x)+2/3*sin(3*x)-1/2*sin(4*x)+2/5*sin(5*x)用matlab画图,求教啊
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