22.已知二元隐函数z=z(x,y)由方程z^2+yz=1-xsiny确定,求全微分dz

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22.已知二元隐函数z=z(x,y)由方程z^2+yz=1-xsiny确定,求全微分dz

2zdz+zdy+ydz=-sinydx-xcosydy
dz=[-sinydx-(xcosy+z)dy]/(2z+y)