main(){int n=6,x;x=f(n);printf("%d!=%d\n",n,x);}f(int n){int y'if(n==1)y=1;else y=n*f(n-1)main(){int n=6,x;x=f(n);printf("%d!=%d\n",n,x);}f(int n){int y'if(n==1) y=1;else y=n*f(n-1);return()}求详解 ——————————————— 特
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main(){int n=6,x;x=f(n);printf("%d!=%d\n",n,x);}f(int n){int y'if(n==1)y=1;else y=n*f(n-1)
main()
{
int n=6,x;
x=f(n);
printf("%d!=%d\n",n,x);
}
f(int n)
{
int y'if(n==1) y=1;
else y=n*f(n-1);
return()
}
求详解 ——————————————— 特别是
else y=n*f(n-1)
1 春风拂面诗意浓
Flipping the check by vernal breeze with rich poetry
2 家乡的味道是槐香
Flavour of hometown lies in pagodatree
3 用真情歌词的交通人
Person of communication via lyric of true love
4 一本值得推荐并珍藏的好书
A wonderful book worth introduction and collection
5 远古的爱情绝响
Voive of love in remote antiquity
#define f(x) x*x main( ) { int i; i=f(4+4)/f(2+2); printf(%d
,i); }
#define f(x) x*x main() {int a=6,b=2,c; C=f(a)?f(b); printf(%d
,c);}
麻烦不要复制百度上的答案,int fa(int x){ return x*x; }int fb(int x){ return x*x*x; }int f(int (*f1)(),int (*f2)(),int x){ return f2(x)-f1(x); }main(){ int i;i=f(fa,fb,2); printf(“%d
”,i);}
main(){int n=6,x;x=f(n);printf(%d!=%d
,n,x);}f(int n){int y'if(n==1)y=1;else y=n*f(n-1)main(){int n=6,x;x=f(n);printf(%d!=%d
,n,x);}f(int n){int y'if(n==1) y=1;else y=n*f(n-1);return()}求详解 ——————————————— 特
#include void f(int*x,int y) {*x=y+1;y=*x+2;} main() {int a=2,b=2; f(&a,b); printf(%d
%d#includevoid f(int*x,int y){*x=y+1;y=*x+2;}main(){int a=2,b=2;f(&a,b);printf(%d
%d,a,b);}
我想搞个X的Y次方的 算法 #include stdafx.hint main(int argc,char* argv[]){int pow(int x,int y);int a,b,c;scanf(%f,%f,&a,&b);c=pow(a,b);printf(%f
,c);return 0;}int pow(int x,int y){int i,z;i=1;z=x;while(i
C语言 答案为什么是8 4 #includevoid f(int y,int *x){y=y+*x;*x=*x+y;}main(){int x=2,y=4;f(y,&x);printf(%d %d
,x,y);}
#includevoid f(int y,int *x){ y=y+*x; *x=*x+y;} void main(){ int x=2,y=4;f(y,&x);printf(%d,%d
,x,y);}
main(){ int x=5; while(x
void f( int y,int *x) {y=y+*x; *x=*x+y;} main( ) { int x=2,y=4; f(y,&x); printf(%d %d
,x,y); } void f( int y,int *x){y=y+*x; *x=*x+y;}main( ){ int x=2,y=4;f(y,&x);printf(%d %d
,x,y);} 执行后输出的结果是 .
#includeint a(int x);int b(int y);int main(){int m,n;n=6;m=a(n);printf(%d
,m);return 0;}int a(int x){x=b(x+3);return x;}int b(int y){return y+1;}
有关浮点数的运算程序A:double f(int x){ return 1.0 / x ; }void main(){ double a ,b;int i ;a = f(10) ;b = f(10) ;i = a == b ;printf( %d
,i ) ;}程序B:double f(int x){ return 1.0 / x ; }void main(){ double a ,b ,c;int i ;a = f(10) ;b
#include #include #include int fun(float x[],int n) /f#include #include #include int fun(float x[],int n)//if(x[j]=>xa)c++;return ;}main(){float x[100]={193.199f,195.673f,195.757f,196.051f,196.092f,196.596f,196.579f,196.763f};system(cls);printf(%d
main( ) {int x=3; do {printf(%d
,x-=2;} while (--x)); }
#include main() {double x=1.0; int n; for(n=0;n
下面程序的运行结果是_______#define N 10#define s(x) x*x#defien f(x) (x*x)main(){int i1,i2;i1=1000/s(N);i2=1000/f(N);printf(%d %d
,i1,i2);}
#define N 10#define s(x) x*x#define f(x) (x*x)main(){int i1,i2;i1=1000/s(N);i2=1000/f(N);printf(%d %d
,i1,i2);}运行结果是?
int fun(static int n) {if(n==1)return 1; else return(n+fun(n-1)); } main() {int x; scanf(%d,&x); int fun(static int n){if(n==1)return 1;elsereturn(n+fun(n-1));}main(){int x;scanf(%d,&x); x=fun(x)+fun(x);printf(%d
,x);}执行程序时,给变量