已知cos(a+TT/3)=sin(a-TT/3),则tana=

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已知cos(a+TT/3)=sin(a-TT/3),则tana=

cos(a+π/3)=sin(a-π/3)
cosa·cosπ/3-sina·sinπ/3=sina·cosπ/3-cosa·sinπ/3
sina·cosπ/3-sina·sinπ/3=cosa·cosπ/3-cosa·sinπ/3
sina(cosπ/3-sinπ/3)=cosa(cosπ/3-sinπ/3 )
sina/cosa=(cosπ/3-sinπ/3 )/(cosπ/3-sinπ/3)
tana=1